滑铁卢华人, 水城百事论坛

复数已经忘了 :-)

aeiou — Tue, 30 Mar 2010 17:15:14 GMT

Reply by aeiou, Tuesday, March 30, 2010, 17:15:

[ No text ]

你在线急等的，不会这么晚才做出来吧:)

yellowsea — Tue, 30 Mar 2010 17:10:17 GMT

Reply by yellowsea, Tuesday, March 30, 2010, 17:10:

[ No text ]

谢谢！本人也做出来了。GUOKE答得完全正确。

aaa — Tue, 30 Mar 2010 16:58:37 GMT

Reply by aaa, Tuesday, March 30, 2010, 16:58:

[ No text ]

当然这个要到高中才会学到:)

yellowsea — Tue, 30 Mar 2010 16:53:28 GMT

Reply by yellowsea, Tuesday, March 30, 2010, 16:53:

[ No text ]

有一种数叫复数:)

yellowsea — Tue, 30 Mar 2010 16:49:32 GMT

Reply by yellowsea, Tuesday, March 30, 2010, 16:49:

[ No text ]

m^2+m+1 = (m^2+m+1/4)+3/4 = (m+1/2)^2+3/4， (m+1/2)^2 肯定是>=0, 所以这条题根本无解。

aeiou — Tue, 30 Mar 2010 16:37:06 GMT

Reply by aeiou, Tuesday, March 30, 2010, 16:37:

[ No text ]

m^2+1/m^2 = -1, (m-1/m)^2 = -3

GuoKe — Tue, 30 Mar 2010 11:41:50 GMT

Reply by GuoKe, Tuesday, March 30, 2010, 11:41:

[ No text ]

如果想解方程得话

yellowsea — Tue, 30 Mar 2010 11:37:20 GMT

Reply by yellowsea, Tuesday, March 30, 2010, 11:37:

显然m不等于1，原始方程乘以m-1就是m^3-1=0,所以m= e^(pi*2/3)或e^(pi*4/3),同样可以算出那两个待求的

m^2+m+1=0

yellowsea — Tue, 30 Mar 2010 11:31:58 GMT

Reply by yellowsea, Tuesday, March 30, 2010, 11:31:

可以肯定m不为零，所以除以m，可以得到m+1/m=-1,平方之可以得到m^2+(1/m)^2=-1,(m-1/m)^2 = m^2+(1/m)^2-2 = -3,所以答案分别是-1,-3

记不记得M=-b/2a (+ -) sqrt( b*b-4ac)/2a ?

wolf — Tue, 30 Mar 2010 11:17:13 GMT

Reply by wolf, Tuesday, March 30, 2010, 11:17:

[ No text ]

在线急等，各位大侠请赐教！

aaa — Tue, 30 Mar 2010 10:35:12 GMT

Reply by aaa, Tuesday, March 30, 2010, 10:35:

[ No text ]

似乎是复数

wolf — Tue, 30 Mar 2010 10:31:18 GMT

Reply by wolf, Tuesday, March 30, 2010, 10:31:

[ No text ]

若M的平方+M+1=0,则M的平方+1/M的平方=? （M-1/M）的平方=?

aaa — Tue, 30 Mar 2010 10:22:37 GMT

Posting by aaa, Tuesday, March 30, 2010, 10:22:

[ No text ]